11213441233 has 4 divisors (see below), whose sum is σ = 11214306288. Its totient is φ = 11212576180.

The previous prime is 11213441231. The next prime is 11213441263. The reversal of 11213441233 is 33214431211.

11213441233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11213441233 - 2¹ = 11213441231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11213441198 and 11213441207.

It is not an unprimeable number, because it can be changed into a prime (11213441231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 412783 + ... + 439108.

It is an arithmetic number, because the mean of its divisors is an integer number (2803576572).

Almost surely, 2^11213441233 is an apocalyptic number.

It is an amenable number.

11213441233 is a deficient number, since it is larger than the sum of its proper divisors (865055).

11213441233 is an equidigital number, since it uses as much as digits as its factorization.

11213441233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 865054.

The product of its digits is 1728, while the sum is 25.

Adding to 11213441233 its reverse (33214431211), we get a palindrome (44427872444).

The spelling of 11213441233 in words is "eleven billion, two hundred thirteen million, four hundred forty-one thousand, two hundred thirty-three".