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11213465001 = 33737821667
BaseRepresentation
bin10100111000101111…
…11110010110101001
31001221111010001011120
422130113332112221
5140431121340001
65052411245453
7544610610534
oct123427762651
931844101146
1011213465001
114834788252
12220b449889
1310992176bb
14785399a1b
154596a8236
hex29c5fe5a9

11213465001 has 4 divisors (see below), whose sum is σ = 14951286672. Its totient is φ = 7475643332.

The previous prime is 11213464993. The next prime is 11213465009. The reversal of 11213465001 is 10056431211.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (11213464993) and next prime (11213465009).

It is a cyclic number.

It is not a de Polignac number, because 11213465001 - 23 = 11213464993 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11213465009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1868910831 + ... + 1868910836.

It is an arithmetic number, because the mean of its divisors is an integer number (3737821668).

Almost surely, 211213465001 is an apocalyptic number.

It is an amenable number.

11213465001 is a deficient number, since it is larger than the sum of its proper divisors (3737821671).

11213465001 is an equidigital number, since it uses as much as digits as its factorization.

11213465001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3737821670.

The product of its (nonzero) digits is 720, while the sum is 24.

Adding to 11213465001 its reverse (10056431211), we get a palindrome (21269896212).

The spelling of 11213465001 in words is "eleven billion, two hundred thirteen million, four hundred sixty-five thousand, one".

Divisors: 1 3 3737821667 11213465001