11214099293 has 2 divisors, whose sum is σ = 11214099294. Its totient is φ = 11214099292.

The previous prime is 11214099289. The next prime is 11214099311. The reversal of 11214099293 is 39299041211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11042436889 + 171662404 = 105083^2 + 13102^2 .

It is a cyclic number.

It is not a de Polignac number, because 11214099293 - 2² = 11214099289 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11214099293.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11214099203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5607049646 + 5607049647.

It is an arithmetic number, because the mean of its divisors is an integer number (5607049647).

Almost surely, 2^11214099293 is an apocalyptic number.

It is an amenable number.

11214099293 is a deficient number, since it is larger than the sum of its proper divisors (1).

11214099293 is an equidigital number, since it uses as much as digits as its factorization.

11214099293 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34992, while the sum is 41.

The spelling of 11214099293 in words is "eleven billion, two hundred fourteen million, ninety-nine thousand, two hundred ninety-three".