Base | Representation |
---|---|
bin | 1010001100101111110111… |
… | …1100111100101010000101 |
3 | 1110201001121200002200100120 |
4 | 2203023331330330222011 |
5 | 2432213012031132201 |
6 | 35503410434532153 |
7 | 2235123322625553 |
oct | 243137574745205 |
9 | 43631550080316 |
10 | 11214125255301 |
11 | 363397a39a521 |
12 | 1311457a37059 |
13 | 634644c99057 |
14 | 2aaaa3616bd3 |
15 | 146a89c54536 |
hex | a32fdf3ca85 |
11214125255301 has 8 divisors (see below), whose sum is σ = 15162760908864. Its totient is φ = 7370786552640.
The previous prime is 11214125255299. The next prime is 11214125255353. The reversal of 11214125255301 is 10355252141211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11214125255301 - 21 = 11214125255299 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11214125257301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26324237476 + ... + 26324237901.
It is an arithmetic number, because the mean of its divisors is an integer number (1895345113608).
Almost surely, 211214125255301 is an apocalyptic number.
It is an amenable number.
11214125255301 is a deficient number, since it is larger than the sum of its proper divisors (3948635653563).
11214125255301 is an equidigital number, since it uses as much as digits as its factorization.
11214125255301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52648475451.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 11214125255301 its reverse (10355252141211), we get a palindrome (21569377396512).
The spelling of 11214125255301 in words is "eleven trillion, two hundred fourteen billion, one hundred twenty-five million, two hundred fifty-five thousand, three hundred one".
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