112142113301 has 4 divisors (see below), whose sum is σ = 112213497504. Its totient is φ = 112070729100.

The previous prime is 112142113297. The next prime is 112142113313. The reversal of 112142113301 is 103311241211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 103311241211 = 41 ⋅2519786371.

It is a cyclic number.

It is not a de Polignac number, because 112142113301 - 2² = 112142113297 is a prime.

It is a super-2 number, since 2×112142113301² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112142113381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35689745 + ... + 35692886.

It is an arithmetic number, because the mean of its divisors is an integer number (28053374376).

Almost surely, 2^112142113301 is an apocalyptic number.

It is an amenable number.

112142113301 is a deficient number, since it is larger than the sum of its proper divisors (71384203).

112142113301 is an equidigital number, since it uses as much as digits as its factorization.

112142113301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71384202.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 112142113301 its reverse (103311241211), we get a palindrome (215453354512).

The spelling of 112142113301 in words is "one hundred twelve billion, one hundred forty-two million, one hundred thirteen thousand, three hundred one".