Base | Representation |
---|---|
bin | 1010001100110000001100… |
… | …0101101110010101100111 |
3 | 1110201001211200021102022101 |
4 | 2203030003011232111213 |
5 | 2432213201112121043 |
6 | 35503423154112531 |
7 | 2235125420330032 |
oct | 243140305562547 |
9 | 43631750242271 |
10 | 11214211442023 |
11 | 3633a14006917 |
12 | 131148087b747 |
13 | 634659ab4405 |
14 | 2aaab0c50019 |
15 | 146a925cb24d |
hex | a330316e567 |
11214211442023 has 2 divisors, whose sum is σ = 11214211442024. Its totient is φ = 11214211442022.
The previous prime is 11214211441987. The next prime is 11214211442041. The reversal of 11214211442023 is 32024411241211.
It is a strong prime.
It is an emirp because it is prime and its reverse (32024411241211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11214211442023 - 241 = 9015188186471 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11214211441982 and 11214211442000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11214211442053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5607105721011 + 5607105721012.
It is an arithmetic number, because the mean of its divisors is an integer number (5607105721012).
Almost surely, 211214211442023 is an apocalyptic number.
11214211442023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11214211442023 is an equidigital number, since it uses as much as digits as its factorization.
11214211442023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 11214211442023 its reverse (32024411241211), we get a palindrome (43238622683234).
The spelling of 11214211442023 in words is "eleven trillion, two hundred fourteen billion, two hundred eleven million, four hundred forty-two thousand, twenty-three".
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