Base | Representation |
---|---|
bin | 1010001100110000010001… |
… | …1001101000111100011111 |
3 | 1110201001220012200000220102 |
4 | 2203030010121220330133 |
5 | 2432213222230040111 |
6 | 35503425301411315 |
7 | 2235126105320126 |
oct | 243140431507437 |
9 | 43631805600812 |
10 | 11214233440031 |
11 | 3633a25471296 |
12 | 1311488109b3b |
13 | 63466151709b |
14 | 2aaab3b38abd |
15 | 146a944c413b |
hex | a3304668f1f |
11214233440031 has 2 divisors, whose sum is σ = 11214233440032. Its totient is φ = 11214233440030.
The previous prime is 11214233439971. The next prime is 11214233440063. The reversal of 11214233440031 is 13004433241211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11214233440031 - 214 = 11214233423647 is a prime.
It is a super-2 number, since 2×112142334400312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11214233439976 and 11214233440003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11214233448031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5607116720015 + 5607116720016.
It is an arithmetic number, because the mean of its divisors is an integer number (5607116720016).
Almost surely, 211214233440031 is an apocalyptic number.
11214233440031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11214233440031 is an equidigital number, since it uses as much as digits as its factorization.
11214233440031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 11214233440031 its reverse (13004433241211), we get a palindrome (24218666681242).
The spelling of 11214233440031 in words is "eleven trillion, two hundred fourteen billion, two hundred thirty-three million, four hundred forty thousand, thirty-one".
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