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112143034213 = 716020433459
BaseRepresentation
bin110100001110000111…
…1101110011101100101
3101201110102220101122121
41220130033232131211
53314132104043323
6123303502225541
711050003030420
oct1503417563545
9351412811577
10112143034213
1143617901471
12198985852b1
13a7624a46a2
1455dba729b7
152db5310a5d
hex1a1c3ee765

112143034213 has 4 divisors (see below), whose sum is σ = 128163467680. Its totient is φ = 96122600748.

The previous prime is 112143034189. The next prime is 112143034219. The reversal of 112143034213 is 312430341211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112143034213 - 25 = 112143034181 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112143034219) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8010216723 + ... + 8010216736.

It is an arithmetic number, because the mean of its divisors is an integer number (32040866920).

Almost surely, 2112143034213 is an apocalyptic number.

It is an amenable number.

112143034213 is a deficient number, since it is larger than the sum of its proper divisors (16020433467).

112143034213 is an equidigital number, since it uses as much as digits as its factorization.

112143034213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16020433466.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 112143034213 its reverse (312430341211), we get a palindrome (424573375424).

The spelling of 112143034213 in words is "one hundred twelve billion, one hundred forty-three million, thirty-four thousand, two hundred thirteen".

Divisors: 1 7 16020433459 112143034213