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1121432223133 is a prime number
BaseRepresentation
bin10000010100011010100…
…100011011110110011101
310222012121112120111202201
4100110122210123312131
5121333143122120013
62215102344251501
7144010064422045
oct20243244336635
93865545514681
101121432223133
113a26622884a2
12161411470b91
138199b104501
143c3c5a8c725
151e2873293dd
hex1051a91bd9d

1121432223133 has 2 divisors, whose sum is σ = 1121432223134. Its totient is φ = 1121432223132.

The previous prime is 1121432223061. The next prime is 1121432223139. The reversal of 1121432223133 is 3313222341211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 757270665369 + 364161557764 = 870213^2 + 603458^2 .

It is an emirp because it is prime and its reverse (3313222341211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1121432223133 - 233 = 1112842288541 is a prime.

It is a super-2 number, since 2×11214322231332 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121432223139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560716111566 + 560716111567.

It is an arithmetic number, because the mean of its divisors is an integer number (560716111567).

Almost surely, 21121432223133 is an apocalyptic number.

It is an amenable number.

1121432223133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121432223133 is an equidigital number, since it uses as much as digits as its factorization.

1121432223133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5184, while the sum is 28.

Adding to 1121432223133 its reverse (3313222341211), we get a palindrome (4434654564344).

The spelling of 1121432223133 in words is "one trillion, one hundred twenty-one billion, four hundred thirty-two million, two hundred twenty-three thousand, one hundred thirty-three".