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1121433412973 is a prime number
BaseRepresentation
bin10000010100011010101…
…000111110010101101101
310222012121121210221220212
4100110122220332111231
5121333143423203343
62215102425552205
7144010110506006
oct20243250762555
93865547727825
101121433412973
113a2662a20435
12161411945665
138199b42cc63
143c3c5cbc1ad
151e2874b1c18
hex1051aa3e56d

1121433412973 has 2 divisors, whose sum is σ = 1121433412974. Its totient is φ = 1121433412972.

The previous prime is 1121433412961. The next prime is 1121433412987. The reversal of 1121433412973 is 3792143341211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 986789917129 + 134643495844 = 993373^2 + 366938^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121433412973 - 26 = 1121433412909 is a prime.

It is a super-2 number, since 2×11214334129732 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1121433412973.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121403412973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560716706486 + 560716706487.

It is an arithmetic number, because the mean of its divisors is an integer number (560716706487).

Almost surely, 21121433412973 is an apocalyptic number.

It is an amenable number.

1121433412973 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121433412973 is an equidigital number, since it uses as much as digits as its factorization.

1121433412973 is an evil number, because the sum of its binary digits is even.

The product of its digits is 108864, while the sum is 41.

The spelling of 1121433412973 in words is "one trillion, one hundred twenty-one billion, four hundred thirty-three million, four hundred twelve thousand, nine hundred seventy-three".