Base | Representation |
---|---|
bin | 10000010100011010101… |
… | …000111110010111011011 |
3 | 10222012121121210222001221 |
4 | 100110122220332113123 |
5 | 121333143423204313 |
6 | 2215102425552511 |
7 | 144010110506224 |
oct | 20243250762733 |
9 | 3865547728057 |
10 | 1121433413083 |
11 | 3a2662a20525 |
12 | 161411945737 |
13 | 8199b430019 |
14 | 3c3c5cbc24b |
15 | 1e2874b1c8d |
hex | 1051aa3e5db |
1121433413083 has 2 divisors, whose sum is σ = 1121433413084. Its totient is φ = 1121433413082.
The previous prime is 1121433413081. The next prime is 1121433413101. The reversal of 1121433413083 is 3803143341211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1121433413083 - 21 = 1121433413081 is a prime.
It is a super-2 number, since 2×11214334130832 (a number of 25 digits) contains 22 as substring.
Together with 1121433413081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1121433413081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560716706541 + 560716706542.
It is an arithmetic number, because the mean of its divisors is an integer number (560716706542).
Almost surely, 21121433413083 is an apocalyptic number.
1121433413083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121433413083 is an equidigital number, since it uses as much as digits as its factorization.
1121433413083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 34.
Adding to 1121433413083 its reverse (3803143341211), we get a palindrome (4924576754294).
The spelling of 1121433413083 in words is "one trillion, one hundred twenty-one billion, four hundred thirty-three million, four hundred thirteen thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •