Base | Representation |
---|---|
bin | 10000010100011010101… |
… | …000111110010111111101 |
3 | 10222012121121210222010012 |
4 | 100110122220332113331 |
5 | 121333143423204432 |
6 | 2215102425553005 |
7 | 144010110506303 |
oct | 20243250762775 |
9 | 3865547728105 |
10 | 1121433413117 |
11 | 3a2662a20556 |
12 | 161411945765 |
13 | 8199b430044 |
14 | 3c3c5cbc273 |
15 | 1e2874b1cb2 |
hex | 1051aa3e5fd |
1121433413117 has 2 divisors, whose sum is σ = 1121433413118. Its totient is φ = 1121433413116.
The previous prime is 1121433413101. The next prime is 1121433413143. The reversal of 1121433413117 is 7113143341211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 945923527396 + 175509885721 = 972586^2 + 418939^2 .
It is a cyclic number.
It is not a de Polignac number, because 1121433413117 - 24 = 1121433413101 is a prime.
It is a super-4 number, since 4×11214334131174 (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121433413417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560716706558 + 560716706559.
It is an arithmetic number, because the mean of its divisors is an integer number (560716706559).
Almost surely, 21121433413117 is an apocalyptic number.
It is an amenable number.
1121433413117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121433413117 is an equidigital number, since it uses as much as digits as its factorization.
1121433413117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6048, while the sum is 32.
Adding to 1121433413117 its reverse (7113143341211), we get a palindrome (8234576754328).
The spelling of 1121433413117 in words is "one trillion, one hundred twenty-one billion, four hundred thirty-three million, four hundred thirteen thousand, one hundred seventeen".
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