Base | Representation |
---|---|
bin | 11001011111111010001111… |
… | …100001011101100001111011 |
3 | 112201001212021110100101220211 |
4 | 121133322033201131201323 |
5 | 104144331410011342110 |
6 | 1034302124430331551 |
7 | 32423064651111013 |
oct | 3137721741354173 |
9 | 481055243311824 |
10 | 112144004012155 |
11 | 32807006749775 |
12 | 106b2314059bb7 |
13 | 4a76198ac247b |
14 | 1d99b27ad8c43 |
15 | ce71c9bca98a |
hex | 65fe8f85d87b |
112144004012155 has 32 divisors (see below), whose sum is σ = 135673439616000. Its totient is φ = 88984386957312.
The previous prime is 112144004012123. The next prime is 112144004012197. The reversal of 112144004012155 is 551210400441211.
It is a cyclic number.
It is not a de Polignac number, because 112144004012155 - 25 = 112144004012123 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1446066321 + ... + 1446143869.
It is an arithmetic number, because the mean of its divisors is an integer number (4239794988000).
Almost surely, 2112144004012155 is an apocalyptic number.
112144004012155 is a deficient number, since it is larger than the sum of its proper divisors (23529435603845).
112144004012155 is a wasteful number, since it uses less digits than its factorization.
112144004012155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82263.
The product of its (nonzero) digits is 6400, while the sum is 31.
Adding to 112144004012155 its reverse (551210400441211), we get a palindrome (663354404453366).
The spelling of 112144004012155 in words is "one hundred twelve trillion, one hundred forty-four billion, four million, twelve thousand, one hundred fifty-five".
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