Base | Representation |
---|---|
bin | 11001100000001011000000… |
… | …100110011000100111001111 |
3 | 112201010120202010121220222111 |
4 | 121200023000212120213033 |
5 | 104200130242324134003 |
6 | 1034314303110324451 |
7 | 32424303046131652 |
oct | 3140130046304717 |
9 | 481116663556874 |
10 | 112162007255503 |
11 | 32813705046987 |
12 | 106b58b9359727 |
13 | 4a77aa78ba09a |
14 | 1d9a954b2b899 |
15 | ce78d04c4e6d |
hex | 6602c09989cf |
112162007255503 has 2 divisors, whose sum is σ = 112162007255504. Its totient is φ = 112162007255502.
The previous prime is 112162007255449. The next prime is 112162007255513. The reversal of 112162007255503 is 305552700261211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112162007255503 is a prime.
It is a super-2 number, since 2×1121620072555032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112162007255513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56081003627751 + 56081003627752.
It is an arithmetic number, because the mean of its divisors is an integer number (56081003627752).
Almost surely, 2112162007255503 is an apocalyptic number.
112162007255503 is a deficient number, since it is larger than the sum of its proper divisors (1).
112162007255503 is an equidigital number, since it uses as much as digits as its factorization.
112162007255503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126000, while the sum is 40.
The spelling of 112162007255503 in words is "one hundred twelve trillion, one hundred sixty-two billion, seven million, two hundred fifty-five thousand, five hundred three".
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