Base | Representation |
---|---|
bin | 10100111001001110… |
… | …10100110011100001 |
3 | 1001221202200111020001 |
4 | 22130213110303201 |
5 | 140433134122441 |
6 | 5053033420001 |
7 | 544660040626 |
oct | 123447246341 |
9 | 31852614201 |
10 | 11217489121 |
11 | 4836a86673 |
12 | 221086a601 |
13 | 1099cc6237 |
14 | 785b2634d |
15 | 459c00731 |
hex | 29c9d4ce1 |
11217489121 has 2 divisors, whose sum is σ = 11217489122. Its totient is φ = 11217489120.
The previous prime is 11217489109. The next prime is 11217489169. The reversal of 11217489121 is 12198471211.
11217489121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10836810000 + 380679121 = 104100^2 + 19511^2 .
It is a cyclic number.
It is not a de Polignac number, because 11217489121 - 25 = 11217489089 is a prime.
It is not a weakly prime, because it can be changed into another prime (11217489181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5608744560 + 5608744561.
It is an arithmetic number, because the mean of its divisors is an integer number (5608744561).
Almost surely, 211217489121 is an apocalyptic number.
It is an amenable number.
11217489121 is a deficient number, since it is larger than the sum of its proper divisors (1).
11217489121 is an equidigital number, since it uses as much as digits as its factorization.
11217489121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8064, while the sum is 37.
It can be divided in two parts, 112174 and 89121, that added together give a triangular number (201295 = T634).
The spelling of 11217489121 in words is "eleven billion, two hundred seventeen million, four hundred eighty-nine thousand, one hundred twenty-one".
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