Base | Representation |
---|---|
bin | 1010001100111100100000… |
… | …0111101000100110000111 |
3 | 1110201101101001100220221022 |
4 | 2203033020013220212013 |
5 | 2432241433331214333 |
6 | 35505131200541355 |
7 | 2235303346505525 |
oct | 243171007504607 |
9 | 43641331326838 |
10 | 11217517054343 |
11 | 363535aa34326 |
12 | 131204392185b |
13 | 634a658b0132 |
14 | 2aad05c8b315 |
15 | 146bd78dbc98 |
hex | a33c81e8987 |
11217517054343 has 4 divisors (see below), whose sum is σ = 11219124846480. Its totient is φ = 11215909262208.
The previous prime is 11217517054333. The next prime is 11217517054357. The reversal of 11217517054343 is 34345071571211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11217517054343 - 28 = 11217517054087 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11217517054294 and 11217517054303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11217517054333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 803885603 + ... + 803899556.
It is an arithmetic number, because the mean of its divisors is an integer number (2804781211620).
Almost surely, 211217517054343 is an apocalyptic number.
11217517054343 is a deficient number, since it is larger than the sum of its proper divisors (1607792137).
11217517054343 is an equidigital number, since it uses as much as digits as its factorization.
11217517054343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1607792136.
The product of its (nonzero) digits is 352800, while the sum is 44.
The spelling of 11217517054343 in words is "eleven trillion, two hundred seventeen billion, five hundred seventeen million, fifty-four thousand, three hundred forty-three".
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