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11219933 is a prime number
BaseRepresentation
bin101010110011…
…001111011101
3210010000212002
4222303033131
510333014213
61040252045
7164240114
oct52631735
923100762
1011219933
11637377a
123911025
13242ac1a
1416c0c7b
15eb9658
hexab33dd

11219933 has 2 divisors, whose sum is σ = 11219934. Its totient is φ = 11219932.

The previous prime is 11219903. The next prime is 11219939. The reversal of 11219933 is 33991211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10413529 + 806404 = 3227^2 + 898^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11219933 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11219896 and 11219905.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11219939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5609966 + 5609967.

It is an arithmetic number, because the mean of its divisors is an integer number (5609967).

Almost surely, 211219933 is an apocalyptic number.

It is an amenable number.

11219933 is a deficient number, since it is larger than the sum of its proper divisors (1).

11219933 is an equidigital number, since it uses as much as digits as its factorization.

11219933 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1458, while the sum is 29.

The square root of 11219933 is about 3349.6168437599. The cubic root of 11219933 is about 223.8704408633.

The spelling of 11219933 in words is "eleven million, two hundred nineteen thousand, nine hundred thirty-three".