11219999999993 has 2 divisors, whose sum is σ = 11219999999994. Its totient is φ = 11219999999992.

The previous prime is 11219999999941. The next prime is 11220000000007. The reversal of 11219999999993 is 39999999991211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5641537036864 + 5578462963129 = 2375192^2 + 2361877^2 .

It is a cyclic number.

It is not a de Polignac number, because 11219999999993 - 2³⁴ = 11202820130809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11219999999899 and 11219999999908.

It is not a weakly prime, because it can be changed into another prime (11219999999093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5609999999996 + 5609999999997.

It is an arithmetic number, because the mean of its divisors is an integer number (5609999999997).

Almost surely, 2^{11219999999993} is an apocalyptic number.

It is an amenable number.

11219999999993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11219999999993 is an equidigital number, since it uses as much as digits as its factorization.

11219999999993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2324522934, while the sum is 89.

The spelling of 11219999999993 in words is "eleven trillion, two hundred nineteen billion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, nine hundred ninety-three".