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112200123132 = 22332879360851
BaseRepresentation
bin110100001111110100…
…1100000001011111100
3101201121102022210221000
41220133221200023330
53314241212420012
6123313302010300
711051265211416
oct1503751401374
9351542283830
10112200123132
1143647054199
12198b3716990
13a771272606
1456054939b6
152dba33addc
hex1a1fa602fc

112200123132 has 48 divisors (see below), whose sum is σ = 290991052800. Its totient is φ = 37386946800.

The previous prime is 112200123121. The next prime is 112200123143. The reversal of 112200123132 is 231321002211.

112200123132 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (112200123121) and next prime (112200123143).

It is a super-2 number, since 2×1122001231322 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 130507 + ... + 491357.

It is an arithmetic number, because the mean of its divisors is an integer number (6062313600).

Almost surely, 2112200123132 is an apocalyptic number.

112200123132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

112200123132 is an abundant number, since it is smaller than the sum of its proper divisors (178790929668).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112200123132 is a wasteful number, since it uses less digits than its factorization.

112200123132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 363743 (or 363735 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 112200123132 its reverse (231321002211), we get a palindrome (343521125343).

The spelling of 112200123132 in words is "one hundred twelve billion, two hundred million, one hundred twenty-three thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 9 12 18 27 36 54 108 2879 5758 8637 11516 17274 25911 34548 51822 77733 103644 155466 310932 360851 721702 1082553 1443404 2165106 3247659 4330212 6495318 9742977 12990636 19485954 38971908 1038890029 2077780058 3116670087 4155560116 6233340174 9350010261 12466680348 18700020522 28050030783 37400041044 56100061566 112200123132