Base | Representation |
---|---|
bin | 11001100000101111100001… |
… | …010100110110001110010111 |
3 | 112201021022221022102002201112 |
4 | 121200233201110312032113 |
5 | 104201301040004340431 |
6 | 1034344305203045235 |
7 | 32430161414433053 |
oct | 3140574124661627 |
9 | 481238838362645 |
10 | 112201211011991 |
11 | 328292a259a432 |
12 | 1070141a67081b |
13 | 4a7b6b4a0352a |
14 | 1d9c7d366ac63 |
15 | ce8927127c2b |
hex | 660be1536397 |
112201211011991 has 2 divisors, whose sum is σ = 112201211011992. Its totient is φ = 112201211011990.
The previous prime is 112201211011811. The next prime is 112201211012173. The reversal of 112201211011991 is 199110112102211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112201211011991 - 218 = 112201210749847 is a prime.
It is a super-2 number, since 2×1122012110119912 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112201211011091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56100605505995 + 56100605505996.
It is an arithmetic number, because the mean of its divisors is an integer number (56100605505996).
Almost surely, 2112201211011991 is an apocalyptic number.
112201211011991 is a deficient number, since it is larger than the sum of its proper divisors (1).
112201211011991 is an equidigital number, since it uses as much as digits as its factorization.
112201211011991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 32.
The spelling of 112201211011991 in words is "one hundred twelve trillion, two hundred one billion, two hundred eleven million, eleven thousand, nine hundred ninety-one".
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