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1122013000117 is a prime number
BaseRepresentation
bin10000010100111101001…
…011111011000110110101
310222021010000102001000101
4100110331023323012311
5121340340312000432
62215240132314101
7144030346066312
oct20247513730665
93867100361011
101122013000117
113a29300a6879
12161553a72931
1381a6152c529
143c43cc6dd09
151e2bd2eb4e7
hex1053d2fb1b5

1122013000117 has 2 divisors, whose sum is σ = 1122013000118. Its totient is φ = 1122013000116.

The previous prime is 1122013000103. The next prime is 1122013000151. The reversal of 1122013000117 is 7110003102211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1117405441476 + 4607558641 = 1057074^2 + 67879^2 .

It is a cyclic number.

It is not a de Polignac number, because 1122013000117 - 223 = 1122004611509 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1122013000094 and 1122013000103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1122013000177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561006500058 + 561006500059.

It is an arithmetic number, because the mean of its divisors is an integer number (561006500059).

Almost surely, 21122013000117 is an apocalyptic number.

It is an amenable number.

1122013000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1122013000117 is an equidigital number, since it uses as much as digits as its factorization.

1122013000117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 1122013000117 its reverse (7110003102211), we get a palindrome (8232016102328).

The spelling of 1122013000117 in words is "one trillion, one hundred twenty-two billion, thirteen million, one hundred seventeen", and thus it is an aban number.