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11220130113 = 33740043371
BaseRepresentation
bin10100111001100010…
…11001100101000001
31001221221122122222120
422130301121211001
5140434323130423
65053210154453
7545021350413
oct123461314501
931857578876
1011220130113
11483851a905
122211722a29
13109a70c35a
147862129b3
1545a072ee3
hex29cc59941

11220130113 has 4 divisors (see below), whose sum is σ = 14960173488. Its totient is φ = 7480086740.

The previous prime is 11220130091. The next prime is 11220130133. The reversal of 11220130113 is 31103102211.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11220130113 - 25 = 11220130081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11220130092 and 11220130101.

It is not an unprimeable number, because it can be changed into a prime (11220130133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1870021683 + ... + 1870021688.

It is an arithmetic number, because the mean of its divisors is an integer number (3740043372).

Almost surely, 211220130113 is an apocalyptic number.

It is an amenable number.

11220130113 is a deficient number, since it is larger than the sum of its proper divisors (3740043375).

11220130113 is an equidigital number, since it uses as much as digits as its factorization.

11220130113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3740043374.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 11220130113 its reverse (31103102211), we get a palindrome (42323232324).

The spelling of 11220130113 in words is "eleven billion, two hundred twenty million, one hundred thirty thousand, one hundred thirteen".

Divisors: 1 3 3740043371 11220130113