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11220134381 is a prime number
BaseRepresentation
bin10100111001100010…
…11010100111101101
31001221221122212211122
422130301122213231
5140434323300011
65053210230325
7545021366021
oct123461324755
931857585748
1011220134381
114838523035
1222117253a5
13109a711291
14786214381
1545a0743db
hex29cc5a9ed

11220134381 has 2 divisors, whose sum is σ = 11220134382. Its totient is φ = 11220134380.

The previous prime is 11220134347. The next prime is 11220134441. The reversal of 11220134381 is 18343102211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10657258756 + 562875625 = 103234^2 + 23725^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11220134381 is a prime.

It is a super-2 number, since 2×112201343812 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11220134381.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11220134281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610067190 + 5610067191.

It is an arithmetic number, because the mean of its divisors is an integer number (5610067191).

Almost surely, 211220134381 is an apocalyptic number.

It is an amenable number.

11220134381 is a deficient number, since it is larger than the sum of its proper divisors (1).

11220134381 is an equidigital number, since it uses as much as digits as its factorization.

11220134381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 11220134381 its reverse (18343102211), we get a palindrome (29563236592).

The spelling of 11220134381 in words is "eleven billion, two hundred twenty million, one hundred thirty-four thousand, three hundred eighty-one".