Base | Representation |
---|---|
bin | 1010001101000110100000… |
… | …0110110101110111111111 |
3 | 1110201122022010001201011001 |
4 | 2203101220012311313333 |
5 | 2432312433001414101 |
6 | 35510253403311131 |
7 | 2235430021413445 |
oct | 243215006656777 |
9 | 43648263051131 |
10 | 11220201201151 |
11 | 3636508082578 |
12 | 131267281b4a7 |
13 | 6350a2a05a97 |
14 | 2ab0bc554b95 |
15 | 146ce338e901 |
hex | a34681b5dff |
11220201201151 has 2 divisors, whose sum is σ = 11220201201152. Its totient is φ = 11220201201150.
The previous prime is 11220201201047. The next prime is 11220201201193. The reversal of 11220201201151 is 15110210202211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11220201201151 - 215 = 11220201168383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11220201202151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610100600575 + 5610100600576.
It is an arithmetic number, because the mean of its divisors is an integer number (5610100600576).
Almost surely, 211220201201151 is an apocalyptic number.
11220201201151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11220201201151 is an equidigital number, since it uses as much as digits as its factorization.
11220201201151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 11220201201151 its reverse (15110210202211), we get a palindrome (26330411403362).
The spelling of 11220201201151 in words is "eleven trillion, two hundred twenty billion, two hundred one million, two hundred one thousand, one hundred fifty-one".
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