Base | Representation |
---|---|
bin | 110100001111111000… |
… | …1000101010011000011 |
3 | 101201121120001202121011 |
4 | 1220133301011103003 |
5 | 3314242220011042 |
6 | 123313412341351 |
7 | 11051321125441 |
oct | 1503761052303 |
9 | 351546052534 |
10 | 112202110147 |
11 | 43648191056 |
12 | 198b4314857 |
13 | a7717b9b6a |
14 | 560584db91 |
15 | 2dba5cea17 |
hex | 1a1fc454c3 |
112202110147 has 2 divisors, whose sum is σ = 112202110148. Its totient is φ = 112202110146.
The previous prime is 112202110087. The next prime is 112202110151. The reversal of 112202110147 is 741011202211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112202110147 - 211 = 112202108099 is a prime.
It is not a weakly prime, because it can be changed into another prime (112202110177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56101055073 + 56101055074.
It is an arithmetic number, because the mean of its divisors is an integer number (56101055074).
Almost surely, 2112202110147 is an apocalyptic number.
112202110147 is a deficient number, since it is larger than the sum of its proper divisors (1).
112202110147 is an equidigital number, since it uses as much as digits as its factorization.
112202110147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 112202110147 its reverse (741011202211), we get a palindrome (853213312358).
The spelling of 112202110147 in words is "one hundred twelve billion, two hundred two million, one hundred ten thousand, one hundred forty-seven".
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