11220214333153 has 4 divisors (see below), whose sum is σ = 12823102095040. Its totient is φ = 9617326571268.

The previous prime is 11220214333103. The next prime is 11220214333171. The reversal of 11220214333153 is 35133341202211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11220214333153 - 2²¹ = 11220212236001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11220214333103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 801443880933 + ... + 801443880946.

It is an arithmetic number, because the mean of its divisors is an integer number (3205775523760).

Almost surely, 2^{11220214333153} is an apocalyptic number.

It is an amenable number.

11220214333153 is a deficient number, since it is larger than the sum of its proper divisors (1602887761887).

11220214333153 is an equidigital number, since it uses as much as digits as its factorization.

11220214333153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1602887761886.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 11220214333153 its reverse (35133341202211), we get a palindrome (46353555535364).

The spelling of 11220214333153 in words is "eleven trillion, two hundred twenty billion, two hundred fourteen million, three hundred thirty-three thousand, one hundred fifty-three".