Base | Representation |
---|---|
bin | 1010001101000110100100… |
… | …1110100110110110111011 |
3 | 1110201122100102110111112122 |
4 | 2203101221032212312323 |
5 | 2432313002310422021 |
6 | 35510255314431455 |
7 | 2235430340336441 |
oct | 243215116466673 |
9 | 43648312414478 |
10 | 11220220014011 |
11 | 3636517761998 |
12 | 1312678b9258b |
13 | 6350a6891a58 |
14 | 2ab0c0c50b91 |
15 | 146ce4d58bab |
hex | a34693a6dbb |
11220220014011 has 2 divisors, whose sum is σ = 11220220014012. Its totient is φ = 11220220014010.
The previous prime is 11220220013993. The next prime is 11220220014061. The reversal of 11220220014011 is 11041002202211.
It is a weak prime.
It is an emirp because it is prime and its reverse (11041002202211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11220220014011 - 210 = 11220220012987 is a prime.
It is not a weakly prime, because it can be changed into another prime (11220220014061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610110007005 + 5610110007006.
It is an arithmetic number, because the mean of its divisors is an integer number (5610110007006).
Almost surely, 211220220014011 is an apocalyptic number.
11220220014011 is a deficient number, since it is larger than the sum of its proper divisors (1).
11220220014011 is an equidigital number, since it uses as much as digits as its factorization.
11220220014011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 11220220014011 its reverse (11041002202211), we get a palindrome (22261222216222).
The spelling of 11220220014011 in words is "eleven trillion, two hundred twenty billion, two hundred twenty million, fourteen thousand, eleven".
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