Base | Representation |
---|---|
bin | 10000010100111101110… |
… | …111001100011001101011 |
3 | 10222021010210202022201121 |
4 | 100110331313030121223 |
5 | 121340401212440042 |
6 | 2215241215400111 |
7 | 144030544361341 |
oct | 20247567143153 |
9 | 3867123668647 |
10 | 1122024343147 |
11 | 3a2936543a84 |
12 | 161557823037 |
13 | 81a639a1496 |
14 | 3c440583991 |
15 | 1e2be2dc367 |
hex | 1053ddcc66b |
1122024343147 has 2 divisors, whose sum is σ = 1122024343148. Its totient is φ = 1122024343146.
The previous prime is 1122024343123. The next prime is 1122024343163. The reversal of 1122024343147 is 7413434202211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1122024343147 is a prime.
It is a super-2 number, since 2×11220243431472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1122024353147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561012171573 + 561012171574.
It is an arithmetic number, because the mean of its divisors is an integer number (561012171574).
Almost surely, 21122024343147 is an apocalyptic number.
1122024343147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122024343147 is an equidigital number, since it uses as much as digits as its factorization.
1122024343147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 34.
Adding to 1122024343147 its reverse (7413434202211), we get a palindrome (8535458545358).
The spelling of 1122024343147 in words is "one trillion, one hundred twenty-two billion, twenty-four million, three hundred forty-three thousand, one hundred forty-seven".
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