11221011300113 has 4 divisors (see below), whose sum is σ = 11459756221440. Its totient is φ = 10982266378788.

The previous prime is 11221011300101. The next prime is 11221011300151. The reversal of 11221011300113 is 31100311012211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11221011300113 is a prime.

It is a super-2 number, since 2×11221011300113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11221011300091 and 11221011300100.

It is not an unprimeable number, because it can be changed into a prime (11221011300613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119372460593 + ... + 119372460686.

It is an arithmetic number, because the mean of its divisors is an integer number (2864939055360).

Almost surely, 2^{11221011300113} is an apocalyptic number.

It is an amenable number.

11221011300113 is a deficient number, since it is larger than the sum of its proper divisors (238744921327).

11221011300113 is an equidigital number, since it uses as much as digits as its factorization.

11221011300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 238744921326.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 11221011300113 its reverse (31100311012211), we get a palindrome (42321322312324).

The spelling of 11221011300113 in words is "eleven trillion, two hundred twenty-one billion, eleven million, three hundred thousand, one hundred thirteen".