Base | Representation |
---|---|
bin | 11001100001000001000001… |
… | …010011110000111100100111 |
3 | 112201100010102211111001211201 |
4 | 121201001001103300330213 |
5 | 104202103030302211101 |
6 | 1034401053514143331 |
7 | 32431425146455642 |
oct | 3141010123607447 |
9 | 481303384431751 |
10 | 112220001210151 |
11 | 3283626512841a |
12 | 10704ba3421b47 |
13 | 4a803ba864393 |
14 | 1d9d696dd0a59 |
15 | ce9176a6de01 |
hex | 6610414f0f27 |
112220001210151 has 2 divisors, whose sum is σ = 112220001210152. Its totient is φ = 112220001210150.
The previous prime is 112220001210139. The next prime is 112220001210157. The reversal of 112220001210151 is 151012100022211.
It is a strong prime.
It is an emirp because it is prime and its reverse (151012100022211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112220001210151 - 211 = 112220001208103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112220001210157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56110000605075 + 56110000605076.
It is an arithmetic number, because the mean of its divisors is an integer number (56110000605076).
Almost surely, 2112220001210151 is an apocalyptic number.
112220001210151 is a deficient number, since it is larger than the sum of its proper divisors (1).
112220001210151 is an equidigital number, since it uses as much as digits as its factorization.
112220001210151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 112220001210151 its reverse (151012100022211), we get a palindrome (263232101232362).
The spelling of 112220001210151 in words is "one hundred twelve trillion, two hundred twenty billion, one million, two hundred ten thousand, one hundred fifty-one".
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