Base | Representation |
---|---|
bin | 11001100001000010000011… |
… | …011001110101111111110101 |
3 | 112201100020022010001111200112 |
4 | 121201002003121311333311 |
5 | 104202112313141144312 |
6 | 1034401355525352405 |
7 | 32431464503045555 |
oct | 3141020331657765 |
9 | 481306263044615 |
10 | 112221110099957 |
11 | 32836784064781 |
12 | 10705252868705 |
13 | 4a805365084b1 |
14 | 1d9d7603a5165 |
15 | ce91de0add22 |
hex | 661083675ff5 |
112221110099957 has 2 divisors, whose sum is σ = 112221110099958. Its totient is φ = 112221110099956.
The previous prime is 112221110099807. The next prime is 112221110100019. The reversal of 112221110099957 is 759990011122211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111963295975441 + 257814124516 = 10581271^2 + 507754^2 .
It is a cyclic number.
It is not a de Polignac number, because 112221110099957 - 214 = 112221110083573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112221110899957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56110555049978 + 56110555049979.
It is an arithmetic number, because the mean of its divisors is an integer number (56110555049979).
Almost surely, 2112221110099957 is an apocalyptic number.
It is an amenable number.
112221110099957 is a deficient number, since it is larger than the sum of its proper divisors (1).
112221110099957 is an equidigital number, since it uses as much as digits as its factorization.
112221110099957 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 204120, while the sum is 50.
The spelling of 112221110099957 in words is "one hundred twelve trillion, two hundred twenty-one billion, one hundred ten million, ninety-nine thousand, nine hundred fifty-seven".
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