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11222220143 is a prime number
BaseRepresentation
bin10100111001110010…
…10111110101101111
31001222002120211222002
422130321113311233
5140440342021033
65053323042515
7545045203661
oct123471276557
931862524862
1011222220143
114839718102
12221237043b
13109ac91764
147865d8531
1545a3373e8
hex29ce57d6f

11222220143 has 2 divisors, whose sum is σ = 11222220144. Its totient is φ = 11222220142.

The previous prime is 11222220077. The next prime is 11222220197. The reversal of 11222220143 is 34102222211.

It is a strong prime.

It is an emirp because it is prime and its reverse (34102222211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11222220143 - 216 = 11222154607 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11222220643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5611110071 + 5611110072.

It is an arithmetic number, because the mean of its divisors is an integer number (5611110072).

Almost surely, 211222220143 is an apocalyptic number.

11222220143 is a deficient number, since it is larger than the sum of its proper divisors (1).

11222220143 is an equidigital number, since it uses as much as digits as its factorization.

11222220143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 11222220143 its reverse (34102222211), we get a palindrome (45324442354).

The spelling of 11222220143 in words is "eleven billion, two hundred twenty-two million, two hundred twenty thousand, one hundred forty-three".