Base | Representation |
---|---|
bin | 110100010000101101… |
… | …1111001010011011111 |
3 | 101201200111202022202201 |
4 | 1220201123321103133 |
5 | 3314321402013211 |
6 | 123320252432331 |
7 | 11052111125065 |
oct | 1504133712337 |
9 | 351614668681 |
10 | 112230110431 |
11 | 43661a7608a |
12 | 199017786a7 |
13 | a77754188a |
14 | 560945c035 |
15 | 2dbccb10c1 |
hex | 1a216f94df |
112230110431 has 2 divisors, whose sum is σ = 112230110432. Its totient is φ = 112230110430.
The previous prime is 112230110407. The next prime is 112230110507. The reversal of 112230110431 is 134011032211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112230110431 - 213 = 112230102239 is a prime.
It is a super-3 number, since 3×1122301104313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 112230110399 and 112230110408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112230113431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56115055215 + 56115055216.
It is an arithmetic number, because the mean of its divisors is an integer number (56115055216).
Almost surely, 2112230110431 is an apocalyptic number.
112230110431 is a deficient number, since it is larger than the sum of its proper divisors (1).
112230110431 is an equidigital number, since it uses as much as digits as its factorization.
112230110431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 112230110431 its reverse (134011032211), we get a palindrome (246241142642).
The spelling of 112230110431 in words is "one hundred twelve billion, two hundred thirty million, one hundred ten thousand, four hundred thirty-one".
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