Base | Representation |
---|---|
bin | 10000010101001110011… |
… | …110100111001111000101 |
3 | 10222021212020022020212212 |
4 | 100111032132213033011 |
5 | 121341434044042013 |
6 | 2215325014353205 |
7 | 144040501024040 |
oct | 20251636471705 |
9 | 3867766266785 |
10 | 1122303112133 |
11 | 3a2a69937275 |
12 | 16161505b805 |
13 | 81aa9677748 |
14 | 3c4695cbc57 |
15 | 1e2d8a056a8 |
hex | 1054e7a73c5 |
1122303112133 has 16 divisors (see below), whose sum is σ = 1292932546560. Its totient is φ = 954251138736.
The previous prime is 1122303112123. The next prime is 1122303112157. The reversal of 1122303112133 is 3312113032211.
It is not a de Polignac number, because 1122303112133 - 210 = 1122303111109 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1122303112099 and 1122303112108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1122303112123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5825060 + ... + 6014642.
It is an arithmetic number, because the mean of its divisors is an integer number (80808284160).
Almost surely, 21122303112133 is an apocalyptic number.
It is an amenable number.
1122303112133 is a deficient number, since it is larger than the sum of its proper divisors (170629434427).
1122303112133 is a wasteful number, since it uses less digits than its factorization.
1122303112133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 196376.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1122303112133 its reverse (3312113032211), we get a palindrome (4434416144344).
The spelling of 1122303112133 in words is "one trillion, one hundred twenty-two billion, three hundred three million, one hundred twelve thousand, one hundred thirty-three".
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