Base | Representation |
---|---|
bin | 11001100001001010101111… |
… | …100001000011111111110011 |
3 | 112201101010101100010212010111 |
4 | 121201022233201003333303 |
5 | 104202240420132440103 |
6 | 1034405541420242151 |
7 | 32432244633666166 |
oct | 3141125741037763 |
9 | 481333340125114 |
10 | 112230440124403 |
11 | 3283a731677187 |
12 | 107070173a0357 |
13 | 4a81392469713 |
14 | 1d9dda7567add |
15 | ce958822a86d |
hex | 6612af843ff3 |
112230440124403 has 2 divisors, whose sum is σ = 112230440124404. Its totient is φ = 112230440124402.
The previous prime is 112230440124391. The next prime is 112230440124431. The reversal of 112230440124403 is 304421044032211.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112230440124403 - 213 = 112230440116211 is a prime.
It is a super-3 number, since 3×1122304401244033 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (112230440121403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56115220062201 + 56115220062202.
It is an arithmetic number, because the mean of its divisors is an integer number (56115220062202).
Almost surely, 2112230440124403 is an apocalyptic number.
112230440124403 is a deficient number, since it is larger than the sum of its proper divisors (1).
112230440124403 is an equidigital number, since it uses as much as digits as its factorization.
112230440124403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 112230440124403 its reverse (304421044032211), we get a palindrome (416651484156614).
The spelling of 112230440124403 in words is "one hundred twelve trillion, two hundred thirty billion, four hundred forty million, one hundred twenty-four thousand, four hundred three".
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