Base | Representation |
---|---|
bin | 10100111001111011… |
… | …00010111010000011 |
3 | 1001222011122102112012 |
4 | 22130331202322003 |
5 | 140441132022201 |
6 | 5053402323135 |
7 | 545060411135 |
oct | 123475427203 |
9 | 31864572465 |
10 | 11223314051 |
11 | 483a2a4a64 |
12 | 22127b94ab |
13 | 109b285641 |
14 | 786801055 |
15 | 45a4a15bb |
hex | 29cf62e83 |
11223314051 has 2 divisors, whose sum is σ = 11223314052. Its totient is φ = 11223314050.
The previous prime is 11223314027. The next prime is 11223314111. The reversal of 11223314051 is 15041332211.
It is a weak prime.
It is an emirp because it is prime and its reverse (15041332211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11223314051 - 214 = 11223297667 is a prime.
It is not a weakly prime, because it can be changed into another prime (11223814051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5611657025 + 5611657026.
It is an arithmetic number, because the mean of its divisors is an integer number (5611657026).
Almost surely, 211223314051 is an apocalyptic number.
11223314051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11223314051 is an equidigital number, since it uses as much as digits as its factorization.
11223314051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 11223314051 its reverse (15041332211), we get a palindrome (26264646262).
The spelling of 11223314051 in words is "eleven billion, two hundred twenty-three million, three hundred fourteen thousand, fifty-one".
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