Base | Representation |
---|---|
bin | 10100111001111100… |
… | …00001111111111001 |
3 | 1001222011212220012212 |
4 | 22130332001333321 |
5 | 140441200111101 |
6 | 5053405144505 |
7 | 545061451334 |
oct | 123476017771 |
9 | 31864786185 |
10 | 11223441401 |
11 | 483a381707 |
12 | 221285b135 |
13 | 109b2cb5b3 |
14 | 78683561b |
15 | 45a4c91bb |
hex | 29cf81ff9 |
11223441401 has 2 divisors, whose sum is σ = 11223441402. Its totient is φ = 11223441400.
The previous prime is 11223441389. The next prime is 11223441431. The reversal of 11223441401 is 10414432211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6400000000 + 4823441401 = 80000^2 + 69451^2 .
It is an emirp because it is prime and its reverse (10414432211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11223441401 - 218 = 11223179257 is a prime.
It is not a weakly prime, because it can be changed into another prime (11223441431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5611720700 + 5611720701.
It is an arithmetic number, because the mean of its divisors is an integer number (5611720701).
Almost surely, 211223441401 is an apocalyptic number.
It is an amenable number.
11223441401 is a deficient number, since it is larger than the sum of its proper divisors (1).
11223441401 is an equidigital number, since it uses as much as digits as its factorization.
11223441401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 11223441401 its reverse (10414432211), we get a palindrome (21637873612).
The spelling of 11223441401 in words is "eleven billion, two hundred twenty-three million, four hundred forty-one thousand, four hundred one".
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