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1122404355031 is a prime number
BaseRepresentation
bin10000010101010100100…
…000110100101111010111
310222022010021210221000211
4100111110200310233113
5121342141003330111
62215343032350251
7144043140413611
oct20252440645727
93868107727024
101122404355031
113a3010aa7593
12161642b45387
1381ac4634b9b
143c478c23db1
151e2e2853521
hex10554834bd7

1122404355031 has 2 divisors, whose sum is σ = 1122404355032. Its totient is φ = 1122404355030.

The previous prime is 1122404354987. The next prime is 1122404355077. The reversal of 1122404355031 is 1305534042211.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1122404355031 - 225 = 1122370800599 is a prime.

It is a super-2 number, since 2×11224043550312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1122404354984 and 1122404355002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1122404350031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561202177515 + 561202177516.

It is an arithmetic number, because the mean of its divisors is an integer number (561202177516).

Almost surely, 21122404355031 is an apocalyptic number.

1122404355031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1122404355031 is an equidigital number, since it uses as much as digits as its factorization.

1122404355031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1122404355031 its reverse (1305534042211), we get a palindrome (2427938397242).

The spelling of 1122404355031 in words is "one trillion, one hundred twenty-two billion, four hundred four million, three hundred fifty-five thousand, thirty-one".