Base | Representation |
---|---|
bin | 11001100001010110110101… |
… | …110011001001101001000111 |
3 | 112201102100220122200211011021 |
4 | 121201112311303021221013 |
5 | 104202444021142300203 |
6 | 1034415530423452011 |
7 | 32433214561533103 |
oct | 3141266563115107 |
9 | 481370818624137 |
10 | 112243430431303 |
11 | 32845198331006 |
12 | 107096418b7007 |
13 | 4a82682826452 |
14 | 1da087a8cc903 |
15 | ce9a988b55bd |
hex | 6615b5cc9a47 |
112243430431303 has 2 divisors, whose sum is σ = 112243430431304. Its totient is φ = 112243430431302.
The previous prime is 112243430431291. The next prime is 112243430431313. The reversal of 112243430431303 is 303134034342211.
It is a strong prime.
It is an emirp because it is prime and its reverse (303134034342211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112243430431303 - 25 = 112243430431271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112243430431313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56121715215651 + 56121715215652.
It is an arithmetic number, because the mean of its divisors is an integer number (56121715215652).
Almost surely, 2112243430431303 is an apocalyptic number.
112243430431303 is a deficient number, since it is larger than the sum of its proper divisors (1).
112243430431303 is an equidigital number, since it uses as much as digits as its factorization.
112243430431303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 112243430431303 its reverse (303134034342211), we get a palindrome (415377464773514).
The spelling of 112243430431303 in words is "one hundred twelve trillion, two hundred forty-three billion, four hundred thirty million, four hundred thirty-one thousand, three hundred three".
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