Base | Representation |
---|---|
bin | 11001100001010111110000… |
… | …010000010000011110100111 |
3 | 112201102110110000001222120212 |
4 | 121201113300100100132213 |
5 | 104203003023222440012 |
6 | 1034420212015450035 |
7 | 32433251100446126 |
oct | 3141276020203647 |
9 | 481373400058525 |
10 | 112244411140007 |
11 | 32845650978a73 |
12 | 1070987622691b |
13 | 4a827aaa6a963 |
14 | 1da0930c57abd |
15 | ce9b04a35b22 |
hex | 6615f04107a7 |
112244411140007 has 2 divisors, whose sum is σ = 112244411140008. Its totient is φ = 112244411140006.
The previous prime is 112244411139997. The next prime is 112244411140033. The reversal of 112244411140007 is 700041114442211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112244411140007 - 214 = 112244411123623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112244411140097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56122205570003 + 56122205570004.
It is an arithmetic number, because the mean of its divisors is an integer number (56122205570004).
Almost surely, 2112244411140007 is an apocalyptic number.
112244411140007 is a deficient number, since it is larger than the sum of its proper divisors (1).
112244411140007 is an equidigital number, since it uses as much as digits as its factorization.
112244411140007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7168, while the sum is 32.
Adding to 112244411140007 its reverse (700041114442211), we get a palindrome (812285525582218).
The spelling of 112244411140007 in words is "one hundred twelve trillion, two hundred forty-four billion, four hundred eleven million, one hundred forty thousand, seven".
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