Base | Representation |
---|---|
bin | 1010001101011010101110… |
… | …1110010111101111100111 |
3 | 1110202011022111102222001012 |
4 | 2203112223232113233213 |
5 | 2432410042413314023 |
6 | 35512552234252435 |
7 | 2236011406524155 |
oct | 243265356275747 |
9 | 43664274388035 |
10 | 11225630604263 |
11 | 3638843908489 |
12 | 1313728b8711b |
13 | 6357597cc34a |
14 | 2ab4756723d5 |
15 | 14700ed66978 |
hex | a35abb97be7 |
11225630604263 has 2 divisors, whose sum is σ = 11225630604264. Its totient is φ = 11225630604262.
The previous prime is 11225630604217. The next prime is 11225630604271. The reversal of 11225630604263 is 36240603652211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11225630604263 - 212 = 11225630600167 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11225630604263.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11225630604203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5612815302131 + 5612815302132.
It is an arithmetic number, because the mean of its divisors is an integer number (5612815302132).
Almost surely, 211225630604263 is an apocalyptic number.
11225630604263 is a deficient number, since it is larger than the sum of its proper divisors (1).
11225630604263 is an equidigital number, since it uses as much as digits as its factorization.
11225630604263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 41.
The spelling of 11225630604263 in words is "eleven trillion, two hundred twenty-five billion, six hundred thirty million, six hundred four thousand, two hundred sixty-three".
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