Base | Representation |
---|---|
bin | 1010001101101011000111… |
… | …1100110010001011010111 |
3 | 1110202120200002201002110211 |
4 | 2203122301330302023113 |
5 | 2432443100140410033 |
6 | 35515000553030251 |
7 | 2236225420061134 |
oct | 243326174621327 |
9 | 43676602632424 |
10 | 11230030013143 |
11 | 363a6a11a3497 |
12 | 13145563b5387 |
13 | 635cab0b6276 |
14 | 2ab771a7558b |
15 | 1471bb1d52cd |
hex | a36b1f322d7 |
11230030013143 has 2 divisors, whose sum is σ = 11230030013144. Its totient is φ = 11230030013142.
The previous prime is 11230030013131. The next prime is 11230030013207. The reversal of 11230030013143 is 34131003003211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11230030013143 is a prime.
It is a super-2 number, since 2×112300300131432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11230030113143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615015006571 + 5615015006572.
It is an arithmetic number, because the mean of its divisors is an integer number (5615015006572).
Almost surely, 211230030013143 is an apocalyptic number.
11230030013143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11230030013143 is an equidigital number, since it uses as much as digits as its factorization.
11230030013143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 11230030013143 its reverse (34131003003211), we get a palindrome (45361033016354).
The spelling of 11230030013143 in words is "eleven trillion, two hundred thirty billion, thirty million, thirteen thousand, one hundred forty-three".
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