Base | Representation |
---|---|
bin | 10000010101111000010… |
… | …001111001010100100011 |
3 | 10222100200002221110100120 |
4 | 100111320101321110203 |
5 | 121344403112441121 |
6 | 2215522350051323 |
7 | 144064045040355 |
oct | 20257021712443 |
9 | 3870602843316 |
10 | 1123004421411 |
11 | 3a32997a0314 |
12 | 16178baa9b43 |
13 | 81b8ba54a52 |
14 | 3c4d47c70d5 |
15 | 1e32a385bc6 |
hex | 10578479523 |
1123004421411 has 4 divisors (see below), whose sum is σ = 1497339228552. Its totient is φ = 748669614272.
The previous prime is 1123004421293. The next prime is 1123004421437. The reversal of 1123004421411 is 1141244003211.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1123004421411 - 218 = 1123004159267 is a prime.
It is a super-2 number, since 2×11230044214112 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1123004421481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 187167403566 + ... + 187167403571.
It is an arithmetic number, because the mean of its divisors is an integer number (374334807138).
Almost surely, 21123004421411 is an apocalyptic number.
1123004421411 is a deficient number, since it is larger than the sum of its proper divisors (374334807141).
1123004421411 is an equidigital number, since it uses as much as digits as its factorization.
1123004421411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 374334807140.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 1123004421411 its reverse (1141244003211), we get a palindrome (2264248424622).
The spelling of 1123004421411 in words is "one trillion, one hundred twenty-three billion, four million, four hundred twenty-one thousand, four hundred eleven".
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