Base | Representation |
---|---|
bin | 10100111010101110… |
… | …11110011001011111 |
3 | 1001222122102202122011 |
4 | 22131113132121133 |
5 | 140444402030302 |
6 | 5054204132051 |
7 | 545202241231 |
oct | 123527363137 |
9 | 31878382564 |
10 | 11230111327 |
11 | 4843117946 |
12 | 2214b37027 |
13 | 109c7c54b6 |
14 | 787690251 |
15 | 45ad955d7 |
hex | 29d5de65f |
11230111327 has 2 divisors, whose sum is σ = 11230111328. Its totient is φ = 11230111326.
The previous prime is 11230111289. The next prime is 11230111337. The reversal of 11230111327 is 72311103211.
It is a strong prime.
It is an emirp because it is prime and its reverse (72311103211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11230111327 - 231 = 9082627679 is a prime.
It is a super-2 number, since 2×112301113272 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11230111298 and 11230111307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11230111337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615055663 + 5615055664.
It is an arithmetic number, because the mean of its divisors is an integer number (5615055664).
Almost surely, 211230111327 is an apocalyptic number.
11230111327 is a deficient number, since it is larger than the sum of its proper divisors (1).
11230111327 is an equidigital number, since it uses as much as digits as its factorization.
11230111327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 11230111327 its reverse (72311103211), we get a palindrome (83541214538).
The spelling of 11230111327 in words is "eleven billion, two hundred thirty million, one hundred eleven thousand, three hundred twenty-seven".
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