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11230131300 = 2235231672269
BaseRepresentation
bin10100111010101111…
…00011010001100100
31001222122110210000220
422131113203101210
5140444403200200
65054204404340
7545202353403
oct123527432144
931878423026
1011230131300
114843130953
122214b466b0
13109c80160b
1478769763a
1545ad9b4a0
hex29d5e3464

11230131300 has 216 divisors, whose sum is σ = 34175312640. Its totient is φ = 2844230400.

The previous prime is 11230131287. The next prime is 11230131301. The reversal of 11230131300 is 313103211.

11230131300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×112301313002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 11230131300.

It is not an unprimeable number, because it can be changed into a prime (11230131301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 41747566 + ... + 41747834.

It is an arithmetic number, because the mean of its divisors is an integer number (158219040).

Almost surely, 211230131300 is an apocalyptic number.

11230131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11230131300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17087656320).

11230131300 is an abundant number, since it is smaller than the sum of its proper divisors (22945181340).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11230131300 is a wasteful number, since it uses less digits than its factorization.

11230131300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 451 (or 377 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11230131300 its reverse (313103211), we get a palindrome (11543234511).

The spelling of 11230131300 in words is "eleven billion, two hundred thirty million, one hundred thirty-one thousand, three hundred".