Base | Representation |
---|---|
bin | 1010001101101011100000… |
… | …1101011001000110001011 |
3 | 1110202120221102022111201210 |
4 | 2203122320031121012023 |
5 | 2432443304031431110 |
6 | 35515015223544203 |
7 | 2236231133520156 |
oct | 243327015310613 |
9 | 43676842274653 |
10 | 11230135030155 |
11 | 363a745501308 |
12 | 13145855bb063 |
13 | 635cc6a95502 |
14 | 2ab7819b0c9d |
15 | 1471c552b520 |
hex | a36b835918b |
11230135030155 has 16 divisors (see below), whose sum is σ = 17971310421504. Its totient is φ = 5988373891680.
The previous prime is 11230135030087. The next prime is 11230135030237. The reversal of 11230135030155 is 55103053103211.
It is not a de Polignac number, because 11230135030155 - 230 = 11229061288331 is a prime.
It is a super-2 number, since 2×112301350301552 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 64376101 + ... + 64550310.
It is an arithmetic number, because the mean of its divisors is an integer number (1123206901344).
Almost surely, 211230135030155 is an apocalyptic number.
11230135030155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11230135030155 is a deficient number, since it is larger than the sum of its proper divisors (6741175391349).
11230135030155 is a wasteful number, since it uses less digits than its factorization.
11230135030155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 128932226.
The product of its (nonzero) digits is 6750, while the sum is 30.
Adding to 11230135030155 its reverse (55103053103211), we get a palindrome (66333188133366).
The spelling of 11230135030155 in words is "eleven trillion, two hundred thirty billion, one hundred thirty-five million, thirty thousand, one hundred fifty-five".
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