Base | Representation |
---|---|
bin | 1010001101101011100000… |
… | …1101011001000111000111 |
3 | 1110202120221102022111211000 |
4 | 2203122320031121013013 |
5 | 2432443304031431330 |
6 | 35515015223544343 |
7 | 2236231133520303 |
oct | 243327015310707 |
9 | 43676842274730 |
10 | 11230135030215 |
11 | 363a745501362 |
12 | 13145855bb0b3 |
13 | 635cc6a9554a |
14 | 2ab7819b0d03 |
15 | 1471c552b560 |
hex | a36b83591c7 |
11230135030215 has 16 divisors (see below), whose sum is σ = 19964684498400. Its totient is φ = 5989405349376.
The previous prime is 11230135030087. The next prime is 11230135030237. The reversal of 11230135030215 is 51203053103211.
11230135030215 is a `hidden beast` number, since 1 + 1 + 2 + 3 + 0 + 1 + 350 + 302 + 1 + 5 = 666.
11230135030215 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11230135030215 - 27 = 11230135030087 is a prime.
It is a super-2 number, since 2×112301350302152 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41593092570 + ... + 41593092839.
It is an arithmetic number, because the mean of its divisors is an integer number (1247792781150).
Almost surely, 211230135030215 is an apocalyptic number.
11230135030215 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11230135030215 is a deficient number, since it is larger than the sum of its proper divisors (8734549468185).
11230135030215 is an equidigital number, since it uses as much as digits as its factorization.
11230135030215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83186185423 (or 83186185417 counting only the distinct ones).
The product of its (nonzero) digits is 2700, while the sum is 27.
Adding to 11230135030215 its reverse (51203053103211), we get a palindrome (62433188133426).
The spelling of 11230135030215 in words is "eleven trillion, two hundred thirty billion, one hundred thirty-five million, thirty thousand, two hundred fifteen".
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