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11230200012133 = 59190342373087
BaseRepresentation
bin1010001101101011110000…
…0101010001110101100101
31110202121002221120221020201
42203122330011101311211
52432443422200342013
635515025504430501
72236232553044044
oct243327405216545
943677087527221
1011230200012133
11363a779155223
1213145a3318431
13636007397c9b
142ab78a48855b
151471cb0b53dd
hexa36bc151d65

11230200012133 has 4 divisors (see below), whose sum is σ = 11420542385280. Its totient is φ = 11039857638988.

The previous prime is 11230200012113. The next prime is 11230200012167. The reversal of 11230200012133 is 33121000203211.

11230200012133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11230200012133 is a prime.

It is a super-2 number, since 2×112302000121332 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11230200012133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11230200012103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95171186485 + ... + 95171186602.

It is an arithmetic number, because the mean of its divisors is an integer number (2855135596320).

Almost surely, 211230200012133 is an apocalyptic number.

It is an amenable number.

11230200012133 is a deficient number, since it is larger than the sum of its proper divisors (190342373147).

11230200012133 is an equidigital number, since it uses as much as digits as its factorization.

11230200012133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 190342373146.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11230200012133 its reverse (33121000203211), we get a palindrome (44351200215344).

The spelling of 11230200012133 in words is "eleven trillion, two hundred thirty billion, two hundred million, twelve thousand, one hundred thirty-three".

Divisors: 1 59 190342373087 11230200012133