Base | Representation |
---|---|
bin | 10100111010110010… |
… | …00010000111110001 |
3 | 1001222200012111221112 |
4 | 22131121002013301 |
5 | 141000003113133 |
6 | 5054221003105 |
7 | 545205562133 |
oct | 123531020761 |
9 | 31880174845 |
10 | 11230519793 |
11 | 4843376819 |
12 | 22150b3495 |
13 | 109c9093ac |
14 | 787759053 |
15 | 45ae26648 |
hex | 29d6421f1 |
11230519793 has 2 divisors, whose sum is σ = 11230519794. Its totient is φ = 11230519792.
The previous prime is 11230519777. The next prime is 11230519843. The reversal of 11230519793 is 39791503211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9188564449 + 2041955344 = 95857^2 + 45188^2 .
It is a cyclic number.
It is not a de Polignac number, because 11230519793 - 24 = 11230519777 is a prime.
It is a super-3 number, since 3×112305197933 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 11230519793.
It is not a weakly prime, because it can be changed into another prime (11230519723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615259896 + 5615259897.
It is an arithmetic number, because the mean of its divisors is an integer number (5615259897).
Almost surely, 211230519793 is an apocalyptic number.
It is an amenable number.
11230519793 is a deficient number, since it is larger than the sum of its proper divisors (1).
11230519793 is an equidigital number, since it uses as much as digits as its factorization.
11230519793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51030, while the sum is 41.
The spelling of 11230519793 in words is "eleven billion, two hundred thirty million, five hundred nineteen thousand, seven hundred ninety-three".
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