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11230519843 is a prime number
BaseRepresentation
bin10100111010110010…
…00010001000100011
31001222200012112000101
422131121002020203
5141000003113333
65054221003231
7545205562234
oct123531021043
931880175011
1011230519843
114843376864
1222150b3517
13109c90941a
1478775908b
1545ae2667d
hex29d642223

11230519843 has 2 divisors, whose sum is σ = 11230519844. Its totient is φ = 11230519842.

The previous prime is 11230519793. The next prime is 11230519847. The reversal of 11230519843 is 34891503211.

It is a strong prime.

It is an emirp because it is prime and its reverse (34891503211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11230519843 is a prime.

It is a super-3 number, since 3×112305198433 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (11230519847) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615259921 + 5615259922.

It is an arithmetic number, because the mean of its divisors is an integer number (5615259922).

Almost surely, 211230519843 is an apocalyptic number.

11230519843 is a deficient number, since it is larger than the sum of its proper divisors (1).

11230519843 is an equidigital number, since it uses as much as digits as its factorization.

11230519843 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 37.

The spelling of 11230519843 in words is "eleven billion, two hundred thirty million, five hundred nineteen thousand, eight hundred forty-three".